Engineering Colleges Latest Cut Off Marks 2013
Cut – off Marks for Engineering Courses to decrease this Year
The cut – off marks required for admission to engineering courses offered by 552 colleges in the State, through unified, single – window admission system, would decrease this year compared to last year, while the cut – off score for admission to medical colleges would increase marginally, according to career consultant and analyst Jayaprakash A. Gandhi.
Addressing The Hindu Education Plus Career Counselling Fair 2013 here on 18th May, 2013, he said the engineering cut – off was expected to decrease because the number of centum scorers in mathematics in the Class XII examinations had come down. The cut – off marks would go up for MBBS because more number of students secured centum in physics and biology.
He said that around 60,000 engineering seats were expected to fall vacant this year. Last year, 55,055 seats fell vacant out of 1,82,459 seats on offer.
Though getting an engineering seat would be a cakewalk in view of proliferation of institutions offering technical courses, students might require a minimum score of 184 to secure admission to the top 40 colleges in the State.
Those interested in pursuing MBBS might need to have a cut – off of anything above 196.
The dental course had lost its sheen in recent years and for the first time in the history of admission to medical colleges in Tamil Nadu, 252 Bachelor of Dental Surgery ( BDS ) seats fell vacant last year out of 909 seats offered by 18 colleges, he said.
He suggested students prefer Electrical and Electronics Engineering, Civil Engineering, Computer Science Engineering and Mechanical Engineering over others, as these engineers would be in great demand in future.
“It is always advisable to select courses on the basis of their future value than selecting them on the basis of their past performance,” he advised.
Those not interested in engineering, could pursue courses in law, agriculture, horticulture, forestry, veterinary science, poultry production, fisheries science and food technology.
The fair was inaugurated by Collector Anshul Mishra. A.N. Brijesh Nair of VIT University, student motivator T.A. Venkateswaran alias ‘Isai Kavi’ Ramanan and IAS topper T. Prabhu Shankar also addressed the students on various topics.
VIT University was the title sponsor of the fair. PSR Engineering College, Renganayagi Varatharaj College of Engineering and Vickram College of Engineering were the associate sponsors.
Einstein College of Engineering at Abishekapatti in Tirunelveli district, PSN College of Engineering and Technology at Melathediyur in Tirunelveli district, DAVAO Medical University, Ratnavel Subramaniam College of Engineering and Technology at Dindigul, PET Engineering College, Pandian Saraswathi Yadav Engineering College at Arasanoor in Sivaganga district and St. Michael Group of Institutions, Kalayarkovil were the co – sponsors. Suriyan FM 93.5 was the radio partner.
TNEA 2013 Cut Off Marks
TNEA 2013 Cutoffs are the minimum marks as ascertained by the Anna University needed to qualify for admissions to the various engineering courses. The TNEA 2013 Cutoffs are determined by the number of applicants, intake per college / university and the previous year’s cutoff. Students can determine the best course they can apply for, using the TNEA 2013 Cutoffs. Students can check out the previous years TNEA 2013 Cutoffs on this page to get an idea.
The TNEA 2013 Cutoffs for engineering are calculated as follows: Total Cut off marks / Total Marks ( 200 marks )
|Subjects||Total Marks||Cut-off Calculation||Cut-Off Marks|
For example if a student secures 198 in Maths, 156 in Physics and 160 in Chemistry then the TNEA Engineering Cutoff marks for that students will be calculated as follows
|Subjects||Total Marks||Cut-off Calculation||Cut-Off Marks|
|Engineering Marks of this student||178Marks/200Marks|
TNEA 2013 Cutoffs for CBSE Board students will be equated with the qualifying examination conducted by the State Board of Tamil Nadu using the Normalization method as follows :
Calculation of Normalization Marks = 100 x actual marks / highest marks of the same board.
For example, a student scores 90 Marks in Math ( CBSE ) and the CBSE Toppers Marks in Maths are 95 Normalization Marks = 100*90/95=94.73648
Note : If the highest marks of a student (Tamil Nadu State Board) in a particular subject are 100 and the highest marks in the same subject of a student belonging to another board is 90 the highest marks for both the boards will be considered to be equal at 100.
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